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basic_file::basic_file - Boost C++ 函数库
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不打开文件来构造一个 basic_file

explicit basic_file(
    const executor_type & ex);
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template<
    typename ExecutionContext>
explicit basic_file(
    ExecutionContext & context,
    constraint_t< is_convertible< ExecutionContext &, execution_context & >::value, defaulted_constraint >  = defaulted_constraint());
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构造并打开一个 basic_file

explicit basic_file(
    const executor_type & ex,
    const char * path,
    file_base::flags open_flags);
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template<
    typename ExecutionContext>
explicit basic_file(
    ExecutionContext & context,
    const char * path,
    file_base::flags open_flags,
    constraint_t< is_convertible< ExecutionContext &, execution_context & >::value, defaulted_constraint >  = defaulted_constraint());
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explicit basic_file(
    const executor_type & ex,
    const std::string & path,
    file_base::flags open_flags);
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template<
    typename ExecutionContext>
explicit basic_file(
    ExecutionContext & context,
    const std::string & path,
    file_base::flags open_flags,
    constraint_t< is_convertible< ExecutionContext &, execution_context & >::value, defaulted_constraint >  = defaulted_constraint());
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在现有的原生文件句柄上构造一个 basic_file

basic_file(
    const executor_type & ex,
    const native_handle_type & native_file);
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在现有的原生文件上构造一个 basic_file

template<
    typename ExecutionContext>
basic_file(
    ExecutionContext & context,
    const native_handle_type & native_file,
    constraint_t< is_convertible< ExecutionContext &, execution_context & >::value, defaulted_constraint >  = defaulted_constraint());
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从另一个 basic_file 移动构造一个。

basic_file(
    basic_file && other);
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从另一个执行器类型的 basic_file 移动构造一个。

template<
    typename Executor1>
basic_file(
    basic_file< Executor1 > && other,
    constraint_t< is_convertible< Executor1, Executor >::value, defaulted_constraint >  = defaulted_constraint());
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